# Line slope calculator 4x+3y=18

**Straight line given by points A[0; 6] and B[3; 2]**

## Calculation:

**Slope-intercept form of line:**y = -1.3333x+6

**Canonical form of the line equation:**4x+3y-18 = 0

**Parametric form of the line equation:**

x = 3t

y = -4t+6 ; t ∈ R

**Slope:**m = -1.3333

**Slope angle of line: φ =**-53°7'48″ = -0.9273 rad

**X intercept:**x

_{0}= 4.5

**Y intercept:**y

_{0}= q = 6

**Distance line from the origin:**d

_{0}= 3.6

**The length of the segment AB: |AB| =**5

**Vector: AB =**(3; -4)

**Normal vector: n =**(4; 3)

**Midpoint of the segment AB: M =**[1.5; 4]

**Perpendicular Bisector equation:**3x-4y+11.5 = 0

**Vector OA = (0; 6) ; |OA| = 6**

**Vector OB = (3; 2) ; |OB| = 3.6056**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 56°18'36″ = 0.9828 rad**